Question

A milkman has 14 litres of one type of milk and 18 litres of other type. Find the least number of equal sized containers required to store all the milk without mixing.

Answer 1

Answer:

2............If it is right please mark my answer as brain list

Answer 2

Answer: Minimum of 16 containers will be required.

Step-by-step explanation:

Volume of one type of milk = 14 litres

Volume of other type of milk = 18 litres

Volume of container for which we will get minimum number of containers is HCF of 14 and 18

14 = 2 × 7

18 = 2 × 3 × 3

HCF = 2

Number of containers of milk of one type = $\frac{14}{2}$  = 7

Number of containers of milk of other type = $\frac{18}{2}$  = 9

Total number of containers = 7 + 9 = 16

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