Question

A milkman has 3 jar Containing 57 litres ,129 litres and 177 litres of pure milk respectively. A measuring can , after a different number of exact measurement of milk in each jar , leaves the same amount of milk unmeasured in each jar . What is the value of the largest such can ?​

Answer 1

Answer:

Ans Is 24 Litres

Step-by-step explanation:

HCF = (129-57) (177-129) f (177-57)

72,48,120

12 , 72 , 48 , 120

2 , 4 , 6 , 10 12×2 =24

3 , 2 , 5 .: 24 Litres

Answer 2

Answer:

The value of of the largest such can is 24 litres.

Step-by-step explanation:

Given,A milkman has 3 jar Containing 57 litres ,129 litres and 177 litres of pure milk respectively. A measuring can , after a different number of exact measurement of milk in each jar , leaves the same amount of milk unmeasured in each jar.

Here we want to find the value of the largest such can.

By HCF rule we can solve this problem.

Here given,leaves the same amount of milk unmeasured in each jar.

So, required largest value of the can = HCF of (129-57),(177-57),(177-129)

= HCF of 72,120,48.

HCF means Highest Common Factor.

Now by prime factorisation,

$72 = 2 \times 2 \times 2 \times 3 \times 3 \\ 120 = 2 \times 2 \times 2 \times 3 \times \times 5 \\ 48 = 2 \times 2 \times 2 \times 2 \times 3$

Highest common factor of 72,120,48 are

$2 \times 2 \times 2 \times 3 = 24$

So HCF of 72,120,48 is 24.

Know more about HCF,

1) https://brainly.in/question/25945206

2) https://brainly.in/question/20353612