Math, asked by deepakrockstar2021, 1 year ago

A milkman sold two of his buffaloes for rs 20000 each. On he one he made a gain of ,5% on in the other a loss of 10% . Find his overall gain or loss . (Hint find cp of each

Answers

Answered by 1007pranjal
12
selling price of two buff.=20,000
gain%=5
loss%=10
combined s.p [for 1 buff.]
20,000+20,000=40,000
100/105 (100)
=4,00,000/21
for other buff.
s.p=rs.20,000
loss%=10
100/90(20,000)
=2,00,000/9

combined c.p=rs.4,00,000/21 +rs.2,00,000/9
=26,00,000/3

overall loss=26,00,000/63 -40,000
8,0000/63
=1269.84
hence=1269.84

sid81686: hii
Chaithanya104s: Bro can u plzz explain me again plzzz
NithishStephenNirmal: hiiiii
Answered by Chaithanya104s
0

Answer:


Step-by-step explanation:

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Secondary SchoolMath 5+3 pts



A milkman sold two of his buffaloes for rs 20000 each. On he one he made a gain of ,5% on in the other a loss of 10% . Find his overall gain or loss . (Hint find cp of each

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Chaithanya104s · Helping Hand

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1007pranjal

1007pranjal Helping Hand

selling price of two buff.=20,000

gain%=5

loss%=10

combined s.p [for 1 buff.]

20,000+20,000=40,000

100/105 (100)

=4,00,000/21

for other buff.

s.p=rs.20,000

loss%=10

100/90(20,000)

=2,00,000/9


combined c.p=rs.4,00,000/21 +rs.2,00,000/9

=26,00,000/3


overall loss=26,00,000/63 -40,000

8,0000/63

=1269.84

hence=1269.84

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