Math, asked by coc6, 1 year ago

a minus b whole square minus b minus C whole square

Answers

Answered by ReetChauhan1112
14
(a-b)²-(b-c)² = [(a-b)-(b-c)][(a-b)+(b-c)] = [a-b-b+c][a-b+b-c] = [a-2b+c][a-c] = a²-2ab+ac-ac+2bc-c² = a²-c²-2ab+2bc
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