Question

A mixture (50 litres) contains wine and water
in the ratio of 3: 2. Find the quantities of wine
and water in the mixture.
30,20
15,10
70,20
80,30​

Answer 1

Answer:

1) 30,20

50÷5 ( the sum ratio)

10=1

10×3= 30

10×2 = 20

Answer 2

Given,

A mixture (50 litres) contains wine and water in the ratio of 3: 2.

To Find,

The quantities of wine and water in the mixture =?

Solution,

We can solve the question as follows:

It is given that a mixture of 50 litres contains wine and water in the ratio of 3: 2. We have to find the quantities of wine and water in the mixture.

$Ratio\: of\: wine\: and\: water = 3:2$

Therefore, the quantity of wine and water in the mixture will be 3x and 2x, when x is the constant of proportionality.

$Quantity\: of\: wine = 3x$

$Quantity\: of\: water = 2x$

Now, the sum of 3x of 2x will be equal to 50 litres.

$3x + 2x = 50$

$5x = 50$

$x = \frac{50}{10} = 5$

Therefore,

$Quantity\: of\: wine = 3x = 3*10 = 30\: litres$

$Quantity\: of\: water = 2x = 2*10 = 20\: litres$

Hence, the quantities of wine and water are 30 and 20 litres respectively.