Chemistry, asked by Sakthisri8955, 9 months ago

A mixture of components A and B will show –ve deviation
when
(a) ∆ Vₘᵢₓ > 0 (b) ∆Hₘᵢₓ < 0
(c) A–B interaction is weaker than A–A and B– B
interactions
(d) A–B interaction is stronger than A–A and B–B
interactions.

Answers

Answered by tejalkaur
7

Answer:

......

Explanation:

d as a- b interaction is stronger than a-a and b-b interactions.

Answered by Anonymous
0

A mixture of components A and B will show a –ve deviation  when (b) ∆Hₘᵢₓ < 0

  • Between molecules of and A and B if the force of attraction in solution is greater than that of between A A and B B, then the propensity of molecules AB to escape from the solution will be lower than that of pure liquids.
  • The total solution pressure will be greater than the vapor pressure corresponding to the ideal solution of the same component A and B.
  • This kind of solution demonstrates negative deviation from Raoult's law.
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