Question

A mixture of gases at ntp for which Gamma is equal to 1.5 is suddenly compressed to 1/9 of its original volume. The final temperature of mixture is

Answer 1

Initial temperature (T1) = 0°C = 273 K

Let Initial volume (V1) = V

Final volume (V2) = V/9
Y=1.5 =2/3

According to adiabatic process,

PV^Y = constant
( as P=T/V )

T/V V^Y-1 = c

TV^1/2 = c

According to question, T1 V1y-1 = T2 V2y-1
273 × V1/2  = T2 ( V /9 )1/2
273 × 3 = T2
T2= 819 K OR 546 DEGREE CELCIUS

Answer 2

Explanation:

☢️PLEASE MARK AS BRAINLIEST☢️