a mixture of helium and methane contains 20% of helium by mass. the mole fraction of methane in the mixture is?
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Answer:
the answer is 1/2.
Explanation:
Let the total mass of mixture is x gram.
Then He gas present in mixture =x/5 g=x/5÷4 mole =x/20 mole
Then CH4 gas present in mixture= 4x/5 g
=4x/5÷16 mole = x/20 mole
Mole fraction=x/20÷(x/20+x/20)= 1/2
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