Question

A mod16 ripple counter is holding the count 10012 wht vill the count be after 31 clock pulse

Answer 1

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In a Mod-N counter, the current state will repeat at Nth pulse.

Current state will be repeated for i×Nth pulse , where i= 1,2,3,...

Given,
It is a Mod-16 counter

The count in the counter (or) Current state = $(1001)_{2}$



So it will repeat the current state at 16th pulse.

The current state will also be same at (16×2) = 32nd pulse

We need the output at 31st pulse which is one less than 1001(9) which is 1000(8).

So for 31th pulse it is (1001)-(0001) = 1000 = 8