A mother and her two sons got a room constructed for 60,000. The elder son contribute s 3/8 of his mother contribution while the younger son contribution 1/2 ohis mother share. How much do three contribute individually
Answers
Answered by
2
let her mother's contribution be x
elder son's share 3/8x
younger son's share. 1/2x
Total money = 60000
x + 3/8x + 1/2x =60000
(8x + 3x + 4x)/8 = 60000
15/8x = 60000
x = 60000×8/15
x = 32000
mother's share =x
=32000
elder son's share = 3/8x
= 3/8 × 32000
= 12000
younger son's share = 1/2x
= 1/2 × 32000
=16000
elder son's share 3/8x
younger son's share. 1/2x
Total money = 60000
x + 3/8x + 1/2x =60000
(8x + 3x + 4x)/8 = 60000
15/8x = 60000
x = 60000×8/15
x = 32000
mother's share =x
=32000
elder son's share = 3/8x
= 3/8 × 32000
= 12000
younger son's share = 1/2x
= 1/2 × 32000
=16000
Answered by
8
Given :
- Let Mother constructed Rs x
- then elder Son contribution = ⅜ x
- younger Son contribution = ½ x
- Total money = 60000
To find :
- How much do three contribute individually
Solution :
= x + ⅜x + ½x
= 60000
= (8 + 3 + 4)/8x
= 60000
= 15/8x
= 60000
= x = 8 x 400
= x = 3200
∴ Mother contribution = Rs.3200
∴ elder Son contribution = ⅜ x 3200 = Rs.1200
∴ younger Son = ½ x 3200 = Rs.1600
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