a mother and her two sons got a room constructed for 60000. the elders and contribute 3/8 of his mother contribution while the youngest and contributes 1 /2of his mother's share .how much do the three contributes individually
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Total contribution = 60000
Let contribution of mother=x
then contribution of elder brother= 3/8 x
contribution of youngest = 1/2 x
A.T.Q
x+3/8x+1/2x=60000
15x/8=60000
15x=60000×8
x=480000/15
x=32000
so contribution of mother is 32000
contribution of elder brother=3/8×32000=12000
contribution of youngest = 1/2×32000
=16000
HOPE IT HELPS
Let contribution of mother=x
then contribution of elder brother= 3/8 x
contribution of youngest = 1/2 x
A.T.Q
x+3/8x+1/2x=60000
15x/8=60000
15x=60000×8
x=480000/15
x=32000
so contribution of mother is 32000
contribution of elder brother=3/8×32000=12000
contribution of youngest = 1/2×32000
=16000
HOPE IT HELPS
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