Question

A mother is five times as old as her daughter after 2 years the mother will be four times as old as her daughter what is the present age of daughter

Answer 1

• Mother = 30 years old &
• Daughter = 6 years old

Step-by-step explanation:

Let,

• The present age of mother be 'a'

According to the question,

Person :- Now :- After 2 years :-

Daughter a a + 2

Mother 5a 5a + 2

We know that,

• 2 years later, Mother's age = 4 times of Daughter's age

Solving,

⟼ 5a + 2 = 4 (a + 2)

⟼ 5a + 2 = 4a + 8

⟼ 5a - 4a = 8 - 2

⟼ a = 6

➤ Present age of Daughter = 6 years

➤ Present age of Mother = 5a = 5 × 6 = 30 years.

• Mother = 30 years old &
• Daughter = 6 years old

Answer 2

The present age of daughter = 6 years

Given :

• A mother is five times as old as her daughter

• After 2 years the mother will be four times as old as her daughter

To find :

The present age of daughter

Solution :

Step 1 of 2 :

Form the equation to calculate present age of daughter

Let present age of daughter = x years

Since mother is five times as old as her daughter

∴ Present age of mother = 5x years

After 2 years :

Age of daughter becomes = (x + 2) years

Age of mother becomes = (5x + 2) years

By the given condition

$\displaystyle \sf 5x + 2 = 4(x + 2)$

Step 2 of 2 :

Calculate present age of daughter

$\displaystyle \sf 5x + 2 = 4(x + 2)$

$\displaystyle \sf{ \implies }5x + 2 = 4x + 8$

$\displaystyle \sf{ \implies }5x - 4x = 8 - 2$

$\displaystyle \sf{ \implies }x = 6$

Present age of daughter = x years = 6 years

Present age of mother = 5x years = 30 years

Hence present age of daughter = 6 years

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