Question

If area of triangle ABC is 48cm square, AD is the median of triangle then find the area of triangle BDC.

Answer 1

Step-by-step explanation:

$\because$ We know that median of a $\triangle$ divides the $\triangle$ in two $\triangle$'s of equal areas.

Area of each new $\triangle$ so formed will be equal to the half of the area of the original $\triangle$.

$\therefore Ar(\triangle BDC) = \frac {1}{2}\times Ar(\triangle ABC)\\</p><p>\therefore Ar(\triangle BDC) = \frac {1}{2}\times 48\\</p><p>\boxed{\red{\therefore Ar(\triangle BDC) =24 \: cm^2}}$