A mother's age is four times as much as the sum of the ages of her three children but after six years her age will be only double the sum of Thier ages .the age of the mther is
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Hi friend!!
Let 'm' be the age of the mother.Let x,y,z be the sum of her three children's age .
Given m=4(x+y+z)
x+y+z=m/4----(1)
After 6 years , mother's age will be m+6, and her children age will be x+6,y+6,z+6
Given m+6=2(x+y+z+18)
substituting (1) ,we get
m+6=2(m/4)+36
m-30=m/2
m/2=30
m=60
Mother's age is 60 years
I hope this will help you ;)
Let 'm' be the age of the mother.Let x,y,z be the sum of her three children's age .
Given m=4(x+y+z)
x+y+z=m/4----(1)
After 6 years , mother's age will be m+6, and her children age will be x+6,y+6,z+6
Given m+6=2(x+y+z+18)
substituting (1) ,we get
m+6=2(m/4)+36
m-30=m/2
m/2=30
m=60
Mother's age is 60 years
I hope this will help you ;)
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