Question

A motor boat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 m s-2 for 8.0 s. How far the boat travel during this time?

Answer 1

We know that s = ut + 1/2at²
According to question, u = 0 [As it was in rest]; a = 3ms⁻² ; t = 8s
s = 0 x 8 + 1/2 x 3 x 8 x 8
s = 3 x 4 x 8
s = 96m

Hope that helps !!  

Answer 2

equation of kinematics: motion :
         s = u t + 1/2 a t²

   here u = 0 m/sec  a = 3.0 m/sec/sec    t = 8.0 sec

           s  = 0 * 8.0 + 1/2 * 3 m/sec² * (8.0 sec)²

      distance travelled in 8 sec = 96 meters