Question

A motor car is travelling at 20m/s on a circular road od radius 100m it is increasing its speed at the rate of 3m/s^2 accereration of motor car is

Answer 1

Answer: 5 m/s^2

Explanation: ignore my comment

given tangential accl At= 3m/s^2

Radial accl Ar = (v^2)/r= (20^2)/100

= 4 m/s^2

Resultant accl = √(At^2 + Ar^2)

= √ (4^2 + 3^2)

= 5 m/s2

Answer 2

Answer:

5 m/s^2

Explanation:

Tengential acceleration =3 m/s^2

Centripetal or Radial acceleration = v^2/r

= (20^2)/100

= 4 m/s^2

Resultant acceleration =

$\sqrt{at { }^{2} + ar {}^{2} }$

[tex] \sqrt{ 4 { }^{2} + 3 {}^{2} } [\tex]

=》 5m/s^2.

Please mark me as brainliest. ..