a motor car slows down from 72km/h to 36km/h at a distance of 25m.if the brakes are applied with the same force calculate(ì)total time in which car comes to rest (ìì)distance traveled by it
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Acceleration = -6 m/s Time to come to rest =3.33s Distance travelled = 8.33m
Calculation: Acceleration formula v2 -u2 =2fs
where v=final velocity, u= initial velocity, f=Acceleration
s=distance 102 -202 =2xfx25 f=-6m/sec2 v=u+ft 0=20 -6t t=20/6=3.33sec
Distance travelled v2=u2+2fs here v=0 so, 0=102 -2x6xs s=100/12=8.33 m
As the car was slowing down, acceleration will be negative.
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