A motor car takes 10 second to cover 30 minute & 12 second to cover 42 meter find the uniform acceleration
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A motor car takes 10s to cover 30m and 12 sec to cover 42m, then we have to find uniform acceleration.
let u is initial velocity and a is acceleration of motor car.
using formula, S = ut + 1/2 at²
case 1 : t = 10s , S = 30m
so, 30m = u(10) + 1/2 a(10)²
⇒30 = 10u + 50a
⇒ 3 = u + 5a ........(1)
velocity after 10s , v = u + a(10) = u + 10a
case 2 : t = 12s , S = 42m
so, 42 = v(12) + 1/2a(12)²
⇒42 = 12(u + 10a) + 1/2 a(144)
⇒42 = 12u + 120a + 72a
⇒42 = 12u + 192a
⇒7 = 2u + 32a ......(2)
solving equations (1) and (2),
eq(2) - 2 × eq(1)
7 - 2 × 3 = 2u + 32a - 2(u + 5a)
⇒1 = 2u + 32a - 2u - 10a
⇒1 = 22a
⇒a = 1/22 = 0.04545 m/s²
hence, acceleration of motor car is 0.04545m/s²
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