A motor cycle of mass 480kg changes its speed from 3m/s to 8m/s.The change in its kinetic enery is what?
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Answered by
1
Original velocity = 3 m/s
New velocity = 8 m /s
Original kinetic energy = 1/2 mv²
New kinetic energy = 1/2 mV²
Change in Kinetic energy =>
=>New kinetic energy - Original kinetic energy
=> 1/2*m*(V²-v²)
=>1/2 * 480 *(64-9)
=> 240*55
=> 13200 kgm/s
Sorry for the late answer and Mark it the brainliest answer
New velocity = 8 m /s
Original kinetic energy = 1/2 mv²
New kinetic energy = 1/2 mV²
Change in Kinetic energy =>
=>New kinetic energy - Original kinetic energy
=> 1/2*m*(V²-v²)
=>1/2 * 480 *(64-9)
=> 240*55
=> 13200 kgm/s
Sorry for the late answer and Mark it the brainliest answer
Nayantripathi:
whats wrong moderator??
Answered by
0
Answer:
the formula is 1/2 m( v'2 - u'2
Explanation:
so 1/2 × 480× 8'2 -3'2 )
so 1/2 × 480×64-9
1×240×55
13200
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