A motor is supplied 600 KW, of which 30% is
lost. This motor is used to operate a crane
whose efficiency is 70%. If this crane lifts a
box of 20 tons, velocity of that box is
Answers
Given : A motor is supplied 600 KW, of which 30% is lost. This motor is used to operate a crane whose efficiency is 70%. this crane lifts a
box of 20 tons,
To Find : velocity of that box is
Solution:
motor is supplied 600 kW
Lost = (30/100)600 = 180 kW
Remaining = 600 - 180 = 420 k W
crane efficiency is 70%
Hence net Power= (70/100)420 kW
= 294 kW
Power = Work Done / Time
Work Done = Force x displacement
d = displacement
Force = mg
m = 20 tonn = 20 k kg
=> 294 k = 20 k * g * d/T
=> d/t = 15
=> d/t = velocity
velocity of that box = 15 m/s
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