Question

A motor of power p0 is used to deliver water at a certain rate through a given horizontal pipe . To increase the rate of flow of water through the same pipe n times the power of the motor is increased to p1 . The ratio of p1 to p0

Answer 1

Let the flow rate, density and velocity of flowing water be  respectively. q,d,v

Force exerted by flowing water =dqv

Power generated by flowing water=F.v= dqv^2

But we know that . q=A.v Where A is area of pipe

Power = pq^3/A^2

Power is directly proportional to A^2

Therefore p0:p1 = n^3 : 1

Answer 2

Answer:

Explanation:

A motor of power p0 is used to deliver water at a certain rate through a given horizontal pipe . To increase the rate of flow of water through the same pipe n times the power of the motor is increased to p1 . The ratio of p1 to p0