Question

a motorboat starting frm rest on a lake accelerates in a straight line at a constant rate of 3.0m square for 8.0s .How far does the boat travel during the time..plss answer..tomorrow is my exam

Answer 1

Here we have,

Initial velocity (u) = 0
Acceleration (a) = 3.0m/s2
Time = 8 s
Therefore, distance (s) covered =?

We know that, s=ut+12at2s=ut+12at2

⇒s=0×8+12 3m/s2×(8s)2⇒s=0×8+12 3m/s2×(8s)2

⇒s=12×3×64m⇒s=12×3×64m

⇒s=3×32 m⇒s=3×32 m

⇒s=96 m⇒s=96 m

Therefore, boat travel a distance of 96 m in the given time.

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Answer 2

Answer:

Given :

Acceleration of boat = 3 m/s²

Time = 8 seconds

To Find :

The distance travelled by the boat during that time

Solution :

From second equation of motion ,

$\\ \star \: {\boxed{\sf{\purple{s = ut + \dfrac{1}{2}a {t}^{2} }}}}$

Where ,

u is initial velocity

t is time

a is acceleration

s is distance travelled

We have ,

• u = 0 [starting from rest]
• t = 8 sec
• a = 8 m/s²

Substituting the values in the equation ,

$\\ : \implies \sf \: s = (0)(8) + \dfrac{1}{2} (3 ) {(8)}^{2}$

$\\ : \implies \sf \: s = \dfrac{1}{2} (3)(64)$

$\\ : \implies \sf \: s = 32 \times 3 \: m$

$\\ : \implies{\underline{\boxed{\pink{\mathfrak{s = 96 \: m}}}}} \: \bigstar$

Hence ,

The distance travelled by the boat during that time is 96 m.