a motorcar is moving with a velocity of 108km/hr and it takes 4sec to stop after the the breaks are applied.find the force excerted by the breaks on motorcar if its mass along with the passengers is 1000Kg.
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u = 108km/hr
t= 4s
v = 0 (since breaks are applied)
m = 1000kg
F=ma
= m(v-u)/t
= m(0-108)/4
= m(27)
= 1000(27)
= 1027
t= 4s
v = 0 (since breaks are applied)
m = 1000kg
F=ma
= m(v-u)/t
= m(0-108)/4
= m(27)
= 1000(27)
= 1027
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