Question

A motorcycle moving with a speed of 5 metre per second is subjected to an acceleration of 0.2 metre per second square calculate the speed of the motor cycle after 10 seconds and the distance travelled in this time.​

Answer 1

Answer:

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u = 5 m/sec

a = 0.2 m/sec ^ 2

t = 10 sec

USING 1ST EQ OF MOTION,

v = u + at

v = 5 + 0.2×10

v = 5 + 2

v = 7 m/sec

FINAL VELOCITY = 7 m/sec

2nd EQ OF MOTION,

s = ut + 1/2 at^2

s = 5 × 10 + 1/2 × 2/10×10×10

s = 50 + 10

s = 60m

DISTANCE = 60 m

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