a motorcycle moving with a speed of 5m/s subjected to acceleration of 0.2m/s*s. calculate the speed of motorcycle.
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u=5m/s
a=0.2m/s^2
v=?
t=10s
v=u+at
v=5+0.2×10
v=7m/s
FINAL VELOCITY=7m/s
s =ut+1/2 at^2
s=5×10+1/2 ×0.2×10×10
s=60m
DISTANCE TRAVELLED =60 m
a=0.2m/s^2
v=?
t=10s
v=u+at
v=5+0.2×10
v=7m/s
FINAL VELOCITY=7m/s
s =ut+1/2 at^2
s=5×10+1/2 ×0.2×10×10
s=60m
DISTANCE TRAVELLED =60 m
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