A motorist starts to travel on a 272km journey at 11:13. At what time will he reach his destination given that he travels at an average speed of 64km/hr. He leaves at 17:55 for the return journey and arrives at the starting point at 23:35. Calculate the time taken and average speed for the return journey?
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T=17/3h S=48km/h
Step-by-step explanation:
1 part- D=272km T=? S=64KM/H T=D/S=272/64=4.25h 2 part- T=17:55-23:35 =5h40m =17/3h now,D=272km T=17/3 S=272÷17/3=48 km/h
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