Question

A moving coil galvanometer has 50 turns and each turn has an area 210 . The magnetic field produced by the magnet inside the galvanometer is 0.02 . The torsional constant of the suspension wire is 10 . When a current flows through the galvanometer, a full scale deflection occurs if the coil rotates by 0.2 . The resistance of the coil of the galvanometer is 50 . This galvanometer is to be converted into an ammeter capable of measuring current in the range 01.0 . For this purpose, a shunt resistance is to be added in parallel to the galvanometer. The value of this shunt resistance, in , is __________.

Answer 1

Answer: hope this will help u

Explanation:

n=50 turns, A=2×10  

−4

m  

2

 

B=0.02T K = 10  

−4

 

Q  

m

​  

=0.2rad R  

g

​  

=50Ω

$$I_A = 0 \ – 1.0 A$$ T=MB=Cθ,M=nIA

BINA=Cθ

0.02×1×50×2×10  

−4

=10  

−4

×0.210

I  

g

​  

=0.1A

For galvanometer, resistance is to be connected to ammeter in shunt.

$$I_g \times R_g = (I – I_g)S$$

$$0.1 \times 50 = (1 – 0.1)S$$

S=  

9

50

​  

=5.55