Math, asked by adi9896, 1 year ago

a natural no. has been divided into 2 parts in ratio 8:5. if the difference of 2 parts is 24 , find the no. and 2 parts​

Answers

Answered by nakshatraroicemathew
0

Let one part be 8 the other be 5x

8x-5x=24

3x=24

x=24/3=8

8x=64

5x=40

The number is 104

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Answered by BrainlyVirat
6

Answer: Original Number = 8

Parts = 64, 40 respectively

Step-by-step explanation:

Let the number be = x

Thus, if the given ratio of parts is 8:5, then, the parts can be written in the form of x as : 8x, 5x

Difference of parts given is to be = 24

We can write that:

8x - 5x = 24 (Difference of parts)

Solve this formed equation further:

=> 3x = 24

=> x = 8

Now, if x = 8, then:

8x = 8 × 8 = 64

5x = 8 × 5 = 40

Other two parts of the original number = 64, 40 respectively

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