Question

A natural num has been divided into two parts in the ratio of 8 :5. If the difference of the two parts is 24 find the number and the two parts
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Answer 1

Answer:

LET THE TWO PARTS BE 8X AND 5X

ATQ

8X-5X=24

3X=24

X=8

PARTS ARE

8X= 8*8=64

5X=5*8=40

Step-by-step explanation:

Answer 2

$\huge\mathfrak{\underline{\underline{Answer:-}}}$

Number :- 104

The parts are :- 64 , 40

$\huge\mathfrak{\underline{\underline{Explanation :-}}}$

We know that a natural number has been divided into two parts.

The difference between two parts is 24

Let the two parts be 8x and 5x.

According to the problem,

8x - 5x = 24

or 3x = 24

or x = 24/3

or x = 8

The parts are :-

8x = 8×8

= 64

5x = 5×8

= 40

Therefore the number is (64+40) = 104