Question

. A net force of 20 N acts on a 5 kg mass kept at
rest. Distance travelled by the mass in 6 s is
(1) 72 m
(2) 36 m
(3) 24 m
(4) 12 m​

Answer 1

Answer:

Given :

Force=F=20N

mass=5kg

initial velocity= u=0 m/s

t=6s

S=distance=?

We know that, F= ma

a=F/m

=20/5

=4m/s²

Distance travelled = S= ut+1/2at²

=0xt+1/2x4x(6)²

=1/2 (4x36)

=144/2

=72 m

Distance travelled = 72m.

if helpful so mark it as a brainaliest please

Answer 2

Answer:

f=m×a

20=5×x

20/5=x

4=x

acceleration=4

s=ut+1/2at^2

s=0×6+1/2×4×6×6

s=0+2×6×6

s=72

answer is 72 metre plz mark me brainliest