A neutral organic compound X of molecular formula C2H6O on oxidation with acidified potassium dichromate gives an acidic compound Y.Compound X reacts wth compound Y on warming in the presence of conc.H2SO4 to give a sweet smelling substance Z. Identifiy X,Y and Z. Write the chemical equation for the reactions involved.
Answers
Y is ethanoic acid (CH3COOH)
Z is ethyl ethanoate (CH3COOC2H5)
First reaction oxidation
C2H5OH -------> CH3COOH
Second reaction esterification
CH3COOH + C2H5OH ----> CH3COOC2H5 + H2O
The compounds are as follow:--
Compound X is ethanol.
Compound Y is ethanoic acid.
Compound Z is ester ethyl ethanoate.
●Compound X with formula C2H6O follow CnH2n+2O which is general formula of alcohol and an alcohal with two carbon is ethanol.
●On oxidation with potassium dichromate alcohol gives an acid as K2Cr2O7 is strong oxidising agent so acid with two carbon is ethanoic acid.It is oxidation reaction.
●Compound X and Y when warmed by conc.H2SO4 give sweet smelling substance which is ester as formed by reaction between alcohol and acid and this reaction is known as esterification reaction .
●So compound ester of 4 carbons is ethylethanoate.
●Reactions are as follow
C2H5OH+K2Cr2O7---->CH2COOH
(Oxidation reaction)
●C2H5OH+CH2COOH+concH2SO4----->CH3CH2COCH2CH3
(esterification reaction)