A neutron having a mass of 1.67*10^-27 kg and moving at 10^8 m/s collides with a neutron at rest and sticks to it . Calculate the speed of combination. ( mass of deutron = 3.34*10^-27 )
Answers
Answered by
4
mass of one neutron = 1.67*10^-27 kgvelocity = 10^8 m/smass of other neutron = 1.67*10^-27 kgvelocity = 0
total mass, m = 3.34*10^-27 kgfinal velocity = v
conserving momentum,
m1v1+m2v2 = mv ⇒ 1.67*10^-27 × 10^8 + 1.67*10^-27 × 0 = 3.34*10^-27 * v ⇒ v = 1.67*10^-27 × 10^8 / 3.34*10^-27 ⇒ v = 10^8 / 2 ⇒ v = 5×10^7 m/s
total mass, m = 3.34*10^-27 kgfinal velocity = v
conserving momentum,
m1v1+m2v2 = mv ⇒ 1.67*10^-27 × 10^8 + 1.67*10^-27 × 0 = 3.34*10^-27 * v ⇒ v = 1.67*10^-27 × 10^8 / 3.34*10^-27 ⇒ v = 10^8 / 2 ⇒ v = 5×10^7 m/s
anishva:
Why is total mass taken as 3.34*10^-27
Similar questions