A new unit of length is equal to 10 m. The area of 5 m² expressed in terms of new unit has magnitude
(1) 0.05
(2) 0.50
(3) 5.05
(4) 5.00
Please answer the question with proper steps.
JinKazama1:
Is answer 0.05 ??
Answers
Answered by
151
Final Answer : 0.05
Let the new unit defined be ' k' units.
Then, we know that
1 k = 10m
=> (1/10)k = 1m
So,
Now,
we see that
![5 {m}^{2} = 5 {( \frac{k}{10}) }^{2} \\ = > \frac{5}{100} {k}^{2} \: \\ = > 0.05 {k}^{2} 5 {m}^{2} = 5 {( \frac{k}{10}) }^{2} \\ = > \frac{5}{100} {k}^{2} \: \\ = > 0.05 {k}^{2}](https://tex.z-dn.net/?f=5+%7Bm%7D%5E%7B2%7D+%3D+5+%7B%28+%5Cfrac%7Bk%7D%7B10%7D%29+%7D%5E%7B2%7D+%5C%5C+%3D+%26gt%3B+%5Cfrac%7B5%7D%7B100%7D+%7Bk%7D%5E%7B2%7D+%5C%3A+%5C%5C+%3D+%26gt%3B+0.05+%7Bk%7D%5E%7B2%7D+)
Therefore, Area of 5m^2 in new unit has magnitude 0.05 .
Let the new unit defined be ' k' units.
Then, we know that
1 k = 10m
=> (1/10)k = 1m
So,
Now,
we see that
Therefore, Area of 5m^2 in new unit has magnitude 0.05 .
Answered by
12
Answer:
0.05
Explanation:
10m = 1n
1 m = 1/10n
area = 5m^2
5m^2 = 5×(1/10)^2
=5×1\100
= 0.05
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