Question

find...fast. ..full process......

Answer 1

answer in the pic...

hope this helps and please mark my answer as brainliest....

Answer 2

Hi ,

Given polynomial f( x ) = x² - 2

To find zeroes of f( x ) , take f( x ) = 0 ,

x² - 2 = 0

x² - ( √2 )² = 0

( x + √2 )( x - √2 ) = 0

Therefore ,

x + √2 = 0 or x - √2 = 0

x = -√2 or x = √2

- √2 , √2 are two zeroes of f ( x ).

verification :

compare f( x ) , with ax² + bx + c , we get

a = 1 , b = 0 , c = -2

i ) sum of the zeroes = - b/a

- √2 + √ 2 = - 0/1

0 = 0

ii ) product of the zeroes = c/a

( -√2 )( √2 ) = -2/1

-2 = -2

I hope this helps you.

: )