A night lamp of rating 100W is operated 6 hours per day. calculate the electricity consumed in month of July and august. answer should be in kWh.
Answers
Answered by
3
Answer:
360
Explanation:
E=Power(inkW)×time=
1000
4×100×6
kWh=2.4kWh
Consumed in 30 days=30×2.4=72
Total cost =72×5=360Rs.
if it,s the right answ. plz mark me as brainliest
Similar questions