A non zero value for c such that the solution set for the inequality x²+ 2cx- 6≤0 in the open interval (-3c, c) is :
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Given : inequality x²+ 2cx- 6≤0 in the open interval (-3c, c)
To find : Value of c
Solution:
x²+ 2cx - 6 ≤ 0
=> (x + c)² - c² - 6 ≤ 0
=> (x + c)² ≤ (c² + 6)
x = - 3c
=> ( -3c + c)² ≤ (c² + 6)
=> 4c² ≤ (c² + 6)
=> 3c² ≤ 6
=> c² ≤ 2
x = c
=> ( c + c)² ≤ (c² + 6)
=> 4c² ≤ (c² + 6)
=> 3c² ≤ 6
=> c² ≤ 2
c lies in [-√2 , √2]
integral value 1 & - 1 both satisfies
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