Question

A number consists of two digit of which tens digit exceeds the unit digit by 3. The number is ten time sum of it's digit.find the number.​

Answer 1

$\huge\underline\mathrm{SOLUTION:-}$

AnswEr:

• Required number will be 30.

Given:

• A number consists of two digit of which tens digit exceeds the unit digit by 3. The number is ten time sum of it's digit.

Need To Find:

• Required number will be = ?

ExPlanation:

Let the ten's digit be x.

And the unit's digit be y.

Therefore:

➠ Number = 10x + y

According to the first statement:

➠ Number = 10 × Sum of digits

➠ 10x + y = 10(x + y)

➠ 10x + y = 10x + 10y

➠ 10x - 10x = 10y - y

➠ 0 = 9y

Now, divide both terms by 9.

➠ y = 0

Hence:

• y = 0

______________________________________

According to the second statement:

➠ Ten's digit = 3 + Unit's digit

➠ x = 3 + y

➠ x = 3 + 0

➠ x = 3

Hence:

• x = 3

ThereFore:

• Required number will be 30.

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Answer 2

Step-by-step explanation:

$let \: the \: number \: be \: 10y + x \\ where \: x \: is \: the \: tens \: digit \: then \: \\ by \: given \: question \\ \\ y = x + 3 \\ 10y + x = 10(x + y) \\ 10y +x = 10x + 10y \\ x - 10x = 0 \: \: = x = 0 \\ \\ y = 0 + 3 \: \: = y = 3 \\ the \: given \: number \\ 10 \times 3 + 0 = 30$

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