a number consists of two digit . when it is divided by the sum of its digits the quotient is 6 with no remainder . when the number is diminisshed by 9 ,the digit are reversed .find the number?
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(10x+y)/x+y=6
10x+y=6x+6y
4x=5y
10x+y-9=10y+x
x-y=9
4x-4y=36
4x-5y=0
y=36
x=45
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