Question

A number consists of two digits and the digit in the ten's place exceds that in the unit's place by 5. If 5 times the sum of the digits be subtracted from the number. The digits of the number are reversed. Then the sum of digits of the number is

Answer 1

Answer:

Sum of the digits of the number is 9(7+2=9)

Step-by-step explanation:

ley the number be xy ie. 10x+y

given x=y+5......(1)

also 10x+y-5(x+y)=10y+x(no.yx)

5x-4y=10y+x ...putting (1)

5y+25-4y=10y+y+5

y+25=11y+5

10y=20 y=2.... putting this value in (1)

x=2+5=7

so required number is 72

and sum of its digits =9

hope it helps