Question

A number consists of two digits whose sum is 9.if 27 subtracted from the Number its digits are reversed. Find the numbers.

Answer 1

let the digit in ones place be x

and the digit in tens place be y

therefore, the two digit no. = 10y+x

the reversing no. = 10x+y

A/Q,

x+y=9

=>x=9-y

and,

10y+x-27=10x+y

=>10y-y+x-10x=27

=>9y-9x=27

=>y-x=27/9

=> y - (9 - y) = 3

=> y - 9 + y = 3

=> 2y-9=3

=>2y=3+9

=>y=12/2=6

therfore, x = 9-6= 3

the no. = 10*6+3 = 63

and the reversing no. = 10*3+6 = 36

hope it helps you!!

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Answer 2

Answer:

36 or 63 can be the number

Step-by-step explanation:

Assuming

x as tens digit

y as ones digit

Their sum :

x + y = 9 ..... (i)

Number formed :

10x + y

Interchanging the digits :

10y + x

According to the question :

➡ (10x + y) - (10y + x) = 27

➡ 9x - 9y = 27

➡ 9(x - y) = 27

➡ x - y = 27/9

➡ x - y = 3 ..... (ii)

Subtracting both the equation :

$\bf \: x + y = 9 \\ { \underline{ \bf{x - y = 3}}} \\ \implies \bf \: 2x = 6 \\ \implies \bf \: x = 3$

Substituting the value of x in equation (i) :

➡ x + y = 9

➡ 3 + y = 9

➡ y = 6

Hence

The number can be 10x + y

or, 10(3) + 6

or, 36 either 63

Hope it helps!!