Math, asked by adithipoojari01, 7 months ago

A number exceeds 20% of itself by 40.find the number?​

Answers

Answered by bishansingh786
3

Step-by-step explanation:

let the number be x

so 20 percent of x =40

20/100 *x =40

1/5 *x=40

x =40*5

x=200

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Answered by swaroopdevarakonda11
4

Step-by-step explanation:

Let us assume, our required number is, ‘x’

Now, represent the statement in mathematical format(aptitude questions are much easier to solve in math representation rather than as statements)..

So, The question says..our number, ‘x’ is just 40 more than 20% of ‘x’

Now, 20% of ‘x’ in mathematical representation is…(20/100)*x

Now, (20/100)*x is equal to 0.2*x (since 20/100=2/10 which is 0.2)

So, now, we write our original statement of ‘x’ being 40 more than 20% of itself…

x=(0.2*x)+40

x-(0.2*x)=40

x-0.2x=40

0.8x=40 (since,1–0.2=0.8)

x=40/0.8

x=50

So, our answer is 50

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