a number exceeds its four-fifth by 13. find the number
adithya02:
ans is 65
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Answered by
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let number be x
x - (4/5)x = 13
So by simplifying (taking common denominator) we get
(5x-4x)/5 = 13
So 5x-4x=65
x=65.
x - (4/5)x = 13
So by simplifying (taking common denominator) we get
(5x-4x)/5 = 13
So 5x-4x=65
x=65.
Answered by
0
let the number be x
fourth-fifth of x = 4x/5
so x-4x/5=13
5x/5-4x/5=13
1x/5=13
so x = 13×5=65
so the no.=65
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fourth-fifth of x = 4x/5
so x-4x/5=13
5x/5-4x/5=13
1x/5=13
so x = 13×5=65
so the no.=65
☆☆please Mark it as a brainliest ☆☆
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