find the conjugate of (3-2i) (2+3i)÷(1+2i) (2-i)
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(6+9i-4i-12i^2)÷(2-1+4i-2i^2)
(6+5i-12i^2)÷(1+4i+-2i^2)
0n multiplying (6+5i-12i^2) and (1+4i+-2i^2)by -1
we will get :
(12i^2-5i-6)÷(2i^2-4i-1)
(6+5i-12i^2)÷(1+4i+-2i^2)
0n multiplying (6+5i-12i^2) and (1+4i+-2i^2)by -1
we will get :
(12i^2-5i-6)÷(2i^2-4i-1)
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