Question

A number is selected from numbers 1 to 25. The probability that it is prime is
(a)$\frac{2}{3}$
(b)$\frac{1}{6}$
(c)$\frac{1}{3}$
(d)$\frac{5}{6}$

Answer 1

SOLUTION :

Here , correct OPTION is not given . Hence no option is correct .

Given : A number is selected from 1 to  25  

Total number of possible outcome = 25

Let E = Event of getting a prime number

Prime number from 1 to  25 are = 2, 3,5,7, 11,13,17, 19, 23

No. of outcomes  favorable to E = 9

Probability ,P(E) = Number of favourable outcomes / total number of outcomes

P(E) = 9/25

Hence, the Probability of getting a prime number from 1 to  25,P(E)  is 9/25.

HOPE THIS ANSWER WILL HELP  YOU….

Answer 2

Total elementary events=25

Prime numbers between them=2,3,5,7,11,13,17,19,23,

So,total favourable elementary events=9

Probability=favourable elementary events/total elementary events

=9/25

All the options have wrong answer.