Question

a number is seven more than four times the other number. if their sum is 122 what are the numbers

Answer 1

Let the first no. be x and the second no. be y
According to question,
y= 4x+7
and x+y= 122
x + 4x +7 = 122
5x =122-7
5x = 115
x = 115/5
x = 23
y = 4×23 + 7
= 92 + 7 =99

Answer 2

Answer:

The answer is 99.

Step-by-step explanation:

Given:

A number is seven more than four times the other number if their sum is $122$.

To find the numbers.

Step 1

Let the first number be $x$

and the second number be $y$.

According to the given question,

$y= 4x+7$

and $x+y= 122$

Step 2

Simplifying both of the equations, we get

$x + 4x +7 = 122$

Adding similar elements

$5x+7 =122$

Subtracting $7$ from both sides of the equation

$5 x+7-7=122-7$

$5x = 115$

$x = 115/5$

Thus, we get

$x = 23$

Step 3

Substituting the value of $x$ in the above equation, we get

$y = 4*23 + 7$

$= 92 + 7$

$=99$

Therefore, the value of $y=99$.

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