A number is twice another number, when the larger number is subtracted from 50, the result is 2 more than when the smaller is subtracted from 40. find the numbers
Answers
Answered by
8
Hi ,
Let one number = x
Second number = 2x
According to the problem given ,
2x - 50 - ( x - 40 ) = 2
2x - 50 - x + 40 = 2
x -10 = 2
x = 2 + 10
x = 12
Therefore ,
Required numbers are,
First number = x = 12
Second number = 2x = 2 × 12 = 24
I hope this helps you.
:)
Let one number = x
Second number = 2x
According to the problem given ,
2x - 50 - ( x - 40 ) = 2
2x - 50 - x + 40 = 2
x -10 = 2
x = 2 + 10
x = 12
Therefore ,
Required numbers are,
First number = x = 12
Second number = 2x = 2 × 12 = 24
I hope this helps you.
:)
Answered by
3
Let First number = x
Second number = 2x
2x - 50 = 2 + ( x - 40 )
2x - 50 - x = 2 - 40
x - 50 = -38
x = 50-38
x = 12
numbers are 12,24
First number = x = 12
Second number = 2x = 2 × 12 = 24
Required numbers are 12,24.
Second number = 2x
2x - 50 = 2 + ( x - 40 )
2x - 50 - x = 2 - 40
x - 50 = -38
x = 50-38
x = 12
numbers are 12,24
First number = x = 12
Second number = 2x = 2 × 12 = 24
Required numbers are 12,24.
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