plzz help me
Factorise :
a²(b+c) - b+c) ³
Answers
Answered by
1
(b+c)-b+c) solving the bracket first so
(-b-c-b+c)*3=(-2b)*3=-8b*3.a*2
taking2 as common =2(-4b*3.
(-b-c-b+c)*3=(-2b)*3=-8b*3.a*2
taking2 as common =2(-4b*3.
satyaprakashjeoxts8r:
thanq sir
Answered by
3
a^2(b+c) - (b+c)^3
= (b+c) {a^2 - (b+c)^2}
=(b+c) {a + (b+c)}{a - (b+c)}
= (b+c) {a + b +c }{ a - b - c}
= (b+c) {a^2 - (b+c)^2}
=(b+c) {a + (b+c)}{a - (b+c)}
= (b+c) {a + b +c }{ a - b - c}
Similar questions
Business Studies,
7 months ago
Math,
7 months ago
Math,
7 months ago
Physics,
1 year ago
Chemistry,
1 year ago