A nut is opened by a wrench of length 10cm. If the least force required is 5.0N , find the koment of force needed to turn the nut
Answers
Answered by
183
distance=10cm=0.1m
force=5N
moment of force=distance×force=0.1×5=0.5Nm
Hope it helps!!!
force=5N
moment of force=distance×force=0.1×5=0.5Nm
Hope it helps!!!
Answered by
72
Here,
Distance,d=10cm(0.1m)
Force,f=5N
So,
Moment of force=fd
=0.1*5=0.5Nm
This is the answer
Distance,d=10cm(0.1m)
Force,f=5N
So,
Moment of force=fd
=0.1*5=0.5Nm
This is the answer
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