A path of width3.5m runs around a circular pool having an area of 962.5m .find the area of the path.
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area of circular pool =962.5m
πrr=962.5
r r=962.5×7÷22
rr=306.25
r=17.5m
now new radius =17.5+3.5
=21 m
area of outer circle =πrr
=π21×21
=1,386
now area of path =ar of outer circle -ar of inner circle
=1386-962.5
ar of path =423.5 ans.
πrr=962.5
r r=962.5×7÷22
rr=306.25
r=17.5m
now new radius =17.5+3.5
=21 m
area of outer circle =πrr
=π21×21
=1,386
now area of path =ar of outer circle -ar of inner circle
=1386-962.5
ar of path =423.5 ans.
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