A object of height 5 cm placed at a distance of 10 cm from the concave lens
of focal length 15.5 cm. Find the magnification and also find the nature and
position of the image.
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Answer:
Given,
Size of object h
o
=5cm
Size of the image h
i
=?
Focal length, f=−10cm
Object distance u=−60cm
Image distance v=?
Using mirror formula,
f
1
=
v
1
+
u
1
−10
1
=
v
1
+
−60
1
v
1
=
60
−6+1
v=−12cm
Hence, the position of the object is at 12 cm in front of the mirror.
Magnification (M)=
h
o
h
i
=
u
−v
=
−60
12
=−0.2
h
i
=−0.2×h
o
h
i
=−0.2×5=−1cm
Height of inverted image is 1cm.
Explanation:
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